Register
Sin2A + sin5A - sinA÷cos2A + cos5A + COSA=Tan2A​
195k views
0 votes
Sin2A + sin5A - sinA÷cos2A + cos5A + COSA=Tan2A​

User Yasen
by
8.7k points

1 Answer

7 votes

Answer:

That is the correct answer

Explanation:

AND the whole solution I hope it helps to you

Sin2A + sin5A - sinA÷cos2A + cos5A + COSA=Tan2A​-example-1
User Shabby
by
8.8k points
← Prev Question Next Question →

Related questions

User Kien Nguyen
asked Sep 25, 2018 126k views
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
Kien Nguyen asked Sep 25, 2018
by Kien Nguyen
7.6k points
1 answer
1 vote
126k views
User JeanK
asked Sep 16, 2019 214k views
SinA-sin5A+sin9A-sin13A / cosA-Cos5A-Cos9A+cos13A = cot4A
JeanK asked Sep 16, 2019
by JeanK
8.6k points
1 answer
3 votes
214k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Write words to match the expression. 24- ( 6+3)
Link Copied!