Question

A swimmer speeds up 1.9 m/s to 3.8 m/s during the last 11.0 seconds of the race. What is the acceleration of the swimmer?

Answer 1

Given :-

Initial speed (v) = 1.9m/s

Final speed (u) = 3.8m/s

Time (t) = 11 s

Formula Used :-

`v = u + a×t`(a = acceleration)

➾
`a = {(u-v)/(t)}`

Solution:-

`a = {(u-v)/(t)}` (putting the value of v, u and t from above)

➾
`a = {(3.8-1.9)/(11)}`

➾
`a = {(1.9)/(11)}`

➾
`a = 0.17 m/s (approx.)`

Therefore, the acceleration rate = 0.17m/s.