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What is the acceleration due to gravity in a region where a simple pendulum having a length 75.000 cm has a period of 1.7357 s?​
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What is the acceleration due to gravity in a region where a simple pendulum having a length 75.000 cm has a period of 1.7357 s?​

User Miyuru Sagarage
by
4.5k points

1 Answer

6 votes

Answer:

Step-by-step explanation:

T = 2π
√(L/g)

(T / 2π)² = L/g

g = 4π²L/T²

g = 4π²(0.75000)/(1.7357)²

g = 9.82814766...

g = 9.8281 m/s²

User Joaquim Rendeiro
by
4.9k points
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