Question

`(-(3n)/(18n^(2) ) )^(-18) * (-6n)^(-15)`

Answer 1

`\left( - (3n)/(18n^2)\right)^(-18) *(-6n)^(-15)\\\\\\= \left(-(1)/(6n) \right)^(-18) * (1)/((-6n)^(15))\\\\\\=\left[(-6n)^(-1)\right]^(-18) * \frac 1{(-6n)^(15)}\\\\\\=(-6n)^(18) * \frac 1{(-6n)^(15)}\\\\=(-6n)^(18-15) \\\\=(-6n)^3\\\\=-216n^3`