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What is the equation of the line that passes through (-6,-2) and had a slope of -1/6

User Hendra
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1 Answer

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Answer:


y = -(1)/(6)x - 3

Explanation:

Slope Intercept Form :
y = mx + b

Using our slope, -1/6, input it for m, then plug the point (-6, -2) for x and y


y = mx+b\\\\-2 = (-1/6)(-6) + b\\\\-2 = 1 + b\\\\b = -3

Equation :
y = -(1)/(6)x - 3

-Chetan K

User Denis Masyukov
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