Question

Solve the following equation simultaneously 2a-3b+10=0, 10a+6b=8​

Answer 1

`2a -3b +10 =0\\\\10a+ 6b -8 =0\\\\\text{Using cross multiplication method}\\\\\\ \frac a{(-3)(-8) - 6(10)} = \frac b{10(10) - 2(-8)} = \frac 1{ 2(6) - (-3)(10)}\\\\\\\implies \frac a{24-60} = \frac b{100+16} = \frac 1{12+30}\\\\\\\\\implies -\frac {a}{36} = \frac b{116} = \frac 1{42}\\\\\\\text{Hence}\\\\a = - (36)/(42) = -\frac 67 \\\\\\ b= (116)/(42) = (58)/(21)`