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Ba^4 * (2ba^4)^-3

Please help

User Edo Post
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1 Answer

8 votes

Answer:

1/(8b^2a^8)

Explanation:

The given expression can be simplified using the rules of exponents.


ba^4*(2ba^4)^(-3)=(ba^4)/((2ba^4)^3)=(ba^4)/(8(ba^4)^3)=(1)/(8(ba^4)^2)=\boxed{(1)/(8b^2a^8)}

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The applicable rules of exponents are ...

a^-b = 1/a^b

(a^b)^c = a^(bc)

(ab)^c = (a^c)(b^c)

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Additional comment

It can be useful to think of an exponent as indicating repeated multiplication: 2^3 = 2×2×2, for example. Of course, the repeated multiplication can be nested: (4^2)^3 = (4^2)×(4^2)×(4^2) = (4×4)×(4×4)×(4×4) = 4^6

Numerator and denominator factors cancel in the usual way.

User Priyeshj
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