Answer:
y -5 = 4(x -2)
Explanation:
The derivative of the function tells you the slope of the line at the point of tangency.
f'(x) = 2x
f'(2) = 4
Then the point-slope equation of the tangent is ...
y -k = m(x -h) . . . . . line with slope m through point (h, k)
y -5 = 4(x -2) . . . . . tangent line with slope 4 through tangent point (2, 5)