Question

Can somebody help me with this question? (Calculus)

Answer 1

y -5 = 4(x -2)

Explanation:

The derivative of the function tells you the slope of the line at the point of tangency.

f'(x) = 2x

f'(2) = 4

Then the point-slope equation of the tangent is ...

y -k = m(x -h) . . . . . line with slope m through point (h, k)

y -5 = 4(x -2) . . . . . tangent line with slope 4 through tangent point (2, 5)