Question

26. The width of a rectangle is 64 inches. The length of the rectangle is twice its width What is the perimeter of the rectangle? A 20 inches B. 40 inches c. 30% inches D. 885 inches​

Answer 1

W = 64
L = 64*2 = 128

P = (64 * 2) + (128 * 2) = 384

Answer 2

`\large \orange{ \frak{Given :}}`

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• Width of rectangle = 64 in.

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• Length of the rectangle is twice its width.

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`\large \orange{ \frak{To \: find:}}`

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• Perimeter of rectangle

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`\large \orange{ \frak{Solution:}}`

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We know :-

• Length = twice of width
• Length = 2 × width
• Length = 2 × 64
• Length =
  `\small \bf 128`

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`\large \orange{ \frak{Digram:}}`

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`\tt 64in.\begin{gathered} \small \large\boxed{\begin{array}{cc} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \\ \end{array}}\end{gathered} \\ \: \: \: \: \sf128in.`

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Formula of perimeter of rectangle:-

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`\bigstar \boxed{\rm{}perimeter \: of \: rectangle = 2(l + w)}`

where :-

l = length of rectangle

w = width of rectangle

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So :-

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`\dashrightarrow\sf{}perimeter \: of \: rectangle = 2(l + w) \\`

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`\dashrightarrow\sf{}perimeter \: of \: rectangle = 2(64 + 128) \\`

`\\ \\`

`\dashrightarrow\sf{}perimeter \: of \: rectangle = 2(64) + 2(128) \\`

`\\ \\`

`\dashrightarrow\sf{}perimeter \: of \: rectangle = 2 * 64+ 2(128) \\`

`\\ \\`

`\dashrightarrow\sf{}perimeter \: of \: rectangle =128+ 2(128) \\`

`\\ \\`

`\dashrightarrow\sf{}perimeter \: of \: rectangle =128+ 2 * 128\\`

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`\dashrightarrow\sf{}perimeter \: of \: rectangle =128+ 256\\`

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`\dashrightarrow\bf{}perimeter \: of \: rectangle =384 \: in\\`

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