Question

If the point (2K-3, K+2) lies on the graph of the equation 2x+y+14=0, find the value of k.?​

Answer 1

k = -2

Explanation:

Substitute 2k-3 for x and k+2 for 2

2x + y + 14 =0

2(2k-3) + (k + 2) + 14 = 0

4k - 6 + k + 2 + 14 = 0

4k + k - 6 + 2 + 14 = 0

5k + 10 = 0

5k + 10 - 10 = 0 - 10

5k = -10

`(5k)/(5) = (-10)/(5)`

k = -2