Question

26/111

Three teams, A, B and C, play in a competition.
games won by A: games won by B = 3:1
games won by B: games won by C = 4:3
Team B has won 8 games.
In total, how many games have the three teams won?

Answer 1

38

To get the number of games C won,you multiply the ratio of B:C,4:3 to ratio of known 8:x to get 6 as the games C won.For A,you multiply the ratio of A:B,3:1 to value of known y:8 to get 24 as the games A won.Add 8+6+24 to get total number of games won.