How do I find the equation of the line y=mx + C, passing through the points M (-2, -3) and T (3, 7)?
How do I find the equation of the line y=mx + C, passing through the points M (-2, -3) and T (3, 7)?
A2A
y = mx + C is often called slope-intercept form.
There are two pieces of information you will need to solve for. #1: The slope, which is m, and #2: the y-intercept, which is C (incidentally I learned this as y = mx + b, instead of y = mx + C, but that is a trivial detail)
Step #1 Find the slope. use the formula slope = (y₂ - y₁)/(x₂ - x₁) => (7 - -3)/3 - -2) = 10/5 = 2. m=2
Step #2 Find the y-intercept. Solve for y = mx + C when x is 2 and x = -2 and y = -3 -3 = 2(-2) + C => -3 = -4 + C add 4 to both sides, 1 = C
Equation: y = 2x + 1.
Check: x = 3 => y = 2(3) + 1 => y = 6 + 1 => y = 7 => (3, 7)
Check: x = -2 => y = 2(-2) + 1 => y = -4 + 1 => y = -3 => (-2, -3)