Question

A car traveling initially at 7.02 m/s accelerates at the rate of 9.04 m/s 2 for 5.85 s. What is its velocity at the end of the acceleration

Answer 1

Apply the equation of motion

v

=

u

+

a

t

The initial velocity is

u

=

5.12

m

s

−

1

The acceleration is

a

=

0.933

m

s

−

2

The time is

t

=

5.7

s

The final velocity is

v

=

u

+

a

t

=

5.12

+

(

0.933

)

×

(

5.7

)

=

10.438

m

s

−

1