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Write an equation of the circle with center (3,-2) and radius 6

User Nouf
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Answer:


\displaystyle (x-3)^2 + (y+2)^2 = 36

Explanation:

We want to write the equation of a circle with a center at (3, -2) and a radius of 6 units.

Recall that the equation of a circle is given by:


\displaystyle (x-h)^2 + (y-k)^2 = r^2

Where (h, k) is the center and r is the radius.

Since our center is at (3, -2), h = 3 and k = -2. r = 6. Substitute:


\displaystyle (x-(3))^2 +(y-(-2))^2 = (6)^2

Simplify:


\displaystyle (x-3)^2 + (y+2)^2 = 36

In conclusion, the equation of the circle will be:


\displaystyle (x-3)^2 + (y+2)^2 = 36

User Martinnovoty
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