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Find the equation of the line

Find the equation of the line-example-1
User Bentolor
by
8.7k points

2 Answers

9 votes

Answer:


y=-(1)/(3) + 5

Explanation:

  1. Pick two points (0,5) & (3,4)
  2. find the slope
    m= (y_(2) - y_1 )/(x_2 - x_1) >>
    m = (4-5)/(3-0) = -(1)/(3)
  3. Find y-intercept (where x is 0) >> y = 5
User CountZero
by
8.6k points
7 votes

Answer:


\mathsf{y=-\frac13x+5}

Explanation:

Slope-intercept form of a linear equation:
\mathsf{y=mx+b}

(where m is the slope and b is the y-intercept)

From inspection of the graph, the y-intercept is at (0, 5)

Therefore, b = 5

Choose another point on the line, e.g. (3, 4)

Now use the slope formula to find the slope:


\mathsf{slope=(y_2-y_1)/(x_2-x_1)}

where:


  • \mathsf{(x_1,y_1)=(0,5)}

  • \mathsf{(x_2,y_2)=(3,4)}


\implies \mathsf{slope=(5-4)/(0-3)=-\frac13}

Therefore, the equation of the line is:


\mathsf{y=-\frac13x+5}

User Bikal Lem
by
7.9k points

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