62.4k views
5 votes
Calculate the elastic potential energy when a 1000 N/m spring is stretched by 6.0 cm from

its natural length
Value
Units
?
Check my answer
Hint 1
Hint 2
Essential GCSE Physics 37.4
< Previous
Gameboard
37. Springs and Elastic Deformation
Essential GCSE Physics 37.6
Next >
Calculate the elastic potential energy when a 1000 N/m spring is stretched by 6.0 cm from its natural length

User Fsimonjetz
by
5.6k points

1 Answer

5 votes

Answer:

F = - k x restoring force

PE = 1/2 k x^2 stored potential energy

PE = 1/2 * 1000 N/m * (.06 m)^2 = 1.8 N-m = 1.8 Joules

User Fire Emblem
by
5.7k points