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An autographed baseball rolls off of a 0.99 m high desk and strikes the floor 0.34 m away

from the desk.
How fast was it rolling on the desk before it fell off? The acceleration of gravity is 9.81 m/s2

User Qble
by
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1 Answer

2 votes

Answer:

Below

Step-by-step explanation:

First, we need to find the time of flight of this projectile :


t=\sqrt{(2dy)/(g) }


t =\sqrt{(2(0.99))/(9.81)


t =\sqrt{(1.98)/(9.81)


t =√(0.20183486238)


t = 0.448489506
seconds

Now we can use this formula to find the initial horizontal velocity :


Dhorizontal = Vhorizontal (time)


0.34 m = Vx(0.448489506) \\0.76m/s^2 = Vx

Therefore the initial velocity of the baseball was 0.76 m/s^2 [Forward]

Hope this helps! Best of luck <3

User Tiziano
by
4.3k points