Question

An autographed baseball rolls off of a 0.99 m high desk and strikes the floor 0.34 m away

from the desk.
How fast was it rolling on the desk before it fell off? The acceleration of gravity is 9.81 m/s2

Answer 1

Below

Step-by-step explanation:

First, we need to find the time of flight of this projectile :

`t=\sqrt{(2dy)/(g) }`

`t =\sqrt{(2(0.99))/(9.81)`

`t =\sqrt{(1.98)/(9.81)`

`t =√(0.20183486238)`

`t = 0.448489506`
`seconds`

Now we can use this formula to find the initial horizontal velocity :

`Dhorizontal = Vhorizontal (time)`

`0.34 m = Vx(0.448489506) \\0.76m/s^2 = Vx`

Therefore the initial velocity of the baseball was 0.76 m/s^2 [Forward]

Hope this helps! Best of luck <3