Question

What is the equation

of a line perpendicular
to y=3/4x+12 that passes
through (12,3)

Answer 1

y = -4/3 x + 19

Explanation:

y = 3/4x + 12

Slope of this line = 3/4 and the slope of the perpendicular line: - 4/3

Point: (12,3)

y-intercept: 3 - (- 4/3)(12) = 3 + 16 = 19

y = - 4/3x + 19

Answer 2

i think the answer is y=4/3x+19 sorry if yhats wrong