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(x^2 + kx + 10) ÷ (x - 1) has a remainder of 4.

I have no idea how to do this, I've tried Synthetic division, remainder theorem etc. and cant figure it out.

User Acabezas
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Answer:

k = -7

Explanation:

Attached are both synthetic division and remainder theorem solutions. Either way, you find the remainder is k+11, which you want to have a value of 4.

k +11 = 4

k = -7 . . . . . subtract 11 from both sides

_____

The second attachment shows the long division that validates this result.

(x^2 + kx + 10) ÷ (x - 1) has a remainder of 4. I have no idea how to do this, I've-example-1
(x^2 + kx + 10) ÷ (x - 1) has a remainder of 4. I have no idea how to do this, I've-example-2
User Rick Kirkham
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