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If 84.5 mol of an ideal gas occupies 21.5 L at 305 K, what is the pressure of the gas? pressure: atm​

1 Answer

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Answer:

98.367 atm

Step-by-step explanation:

For this, you must use the equation PV=nRT. Since you are looking for P, rearrange the equation so that P= nRT/V.

Now collect the information you have:

n (mol) = 84.5

R (ideal gas constant to find atm not every case) = .08206

T (temperature) = 305 K (always convert to kelvin)

V (volume in liters) = 21.5

Now Use P= (85.5 mol)×(.08206)×(305 K)/(21.5) to get your answer in atm

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