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PLSSSS HELP ME WITH THIS QUESTION!!!

PLSSSS HELP ME WITH THIS QUESTION!!!-example-1

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91°-32°=
59°
The line EF total angles must equal 180°. Therefore angle EOB is 89°, (180-91). Then line AB must also equal 180°. And angle EOB is 89° and angle COA is 32°. Take 89+32 which is 121. 180-121=59. Finally, that leaves angle COE with an angle measure of 59°.
User Gijs Overvliet
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Given,

∠AOE = 30°

∠DOB = 40°

So, ∠EOD = 180 - (30+40) [angles on a straight line]

= 180 - 70

= 110

∠EOD = ∠COF [ vertically opposite angle]

∴ ∠COF = 110°

User Panoskarajohn
by
8.0k points

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