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8 * √(2) = {2}^(n)
work out the Value of n
with steps ​

User Breen Ho
by
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1 Answer

2 votes

Answer:

n = 7/2

Explanation:

We are given the equation:-


\displaystyle \large{8 * √(2) = {2}^(n) }

To solve an exponential equation, first, we convert the whole equation with same base.

Let our main base is 2 for whole equation, the following number must be:-

  • 8 = 2•2•2 = 2^3
  • √2 = 2^(1/2) —> Law of Exponent

From √2 = 2^(1/2) comes from:-


\displaystyle \large{ {a}^{ (m)/( n ) } = \sqrt[n]{ {a}^(m) } }

  • m = 1
  • n = 2
  • a = 2


\displaystyle \large{ {2}^{ (1)/( 2 ) } = √(2) }

Rewrite the equation with base 2.


\displaystyle \large{ {2}^(3) * {2}^{ (1)/(2) } = {2}^(n) }

Recall the law of exponent:-


\displaystyle \large{ {a}^(m) * {a}^(n) = {a}^(m + n) }

Therefore:-


\displaystyle \large{ {2}^{3 + (1)/(2) } = {2}^(n) } \\ \displaystyle \large{ {2}^{ (6)/(2) + (1)/(2) } = {2}^(n) } \\ \displaystyle \large{ {2}^{ (7)/(2) } = {2}^(n) }

Compare the exponent and thus:-

n = 7/2.

User Parth Anjaria
by
4.4k points