Question

F(x) = 732

g(x) = 3x + 2
Find
(1) (a). Include any restrictions on the domain.
, 3 > 0
OA () (x) = 0 + 0
B. (4) (z) = 2, 3
c. (4) (x) = x +
OD. () () + -1

Answer 1

• Option D

Explanation:

Given:

• 
  `f(x) = \sqrt[3]{3x}`
• 
  `g(x)=3x+2`

Find (f/g)(x):

• 
  `(f/g)(x)=f(x)/g(x)=\sqrt[3]{3x}/(3x+2)`

The restriction is, the denominator can't be zero:

• 3x + 2 ≠ 0 ⇒ 3x ≠ -2 ⇒ x ≠ -2/3

Correct choice is D