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Given g(x) = 1/2 (x-4)^2 , what is the value of g(10) .
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Given g(x) = 1/2 (x-4)^2 , what is the value of g(10) .

User Twomz
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Answer:18

Explanation:


\text{if} \quad x=10,\\ g(10)=(1)/(2)(10-4)^2\\ g(10)=(1)/(2)(6)^2\\ g(10)=(1)/(2)36\\ g(10)=18

User Voigtan
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