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What is the 8th term of the sequence whose first term is 64 and common ratio is 1/2?

1 Answer

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Here's the solution :


  • nth \: \: term = ar {}^(n - 1)

here,

  • n = 8th term

  • r = 1/2

  • a = 64

now, let's find the 8th term :


  • 64 * { \bigg( (1)/(2) \bigg ) }^(8 - 1)


  • 64 * \bigg(\frac{1}{2 {}^(7) } \bigg)


  • 64 * (1)/(128)


  • (1)/(2) \: \: \: o r \: \: \: 0.5
User Swarit Agarwal
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