Question

What is the 8th term of the sequence whose first term is 64 and common ratio is 1/2?

Answer 1

Here's the solution :

• 
  `nth \: \: term = ar {}^(n - 1)`

here,

• n = 8th term

• r = 1/2

• a = 64

now, let's find the 8th term :

• 
  `64 * { \bigg( (1)/(2) \bigg ) }^(8 - 1)`

• 
  `64 * \bigg(\frac{1}{2 {}^(7) } \bigg)`

• 
  `64 * (1)/(128)`

• 
  `(1)/(2) \: \: \: o r \: \: \: 0.5`