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If H between N and S, HN = 20 cm , and HS = 6 cm , then NS=

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Answer:

Step-by-step explanation: I always like to make sure I am clear about the question. It seems like the question is:

you have 3 variables; H, N, and S. Using ( ) to represent multiplication

If

(H)(N) = 20cm [H times N is equal to 20 cm]

and

(H)(S) = 6cm [H times S is equal to 6 cm]

then what does

(N)(S) = ? [N times S equals what?]

since H is used in both equations, we know they are the same number, so H has to be a number that is a factor (meaning what are the individual numbers in a multiplication equation)

Since (H)(N) = 20 H represents one of the individual numbers. And the factors of 20 are (1, 2, 4, 5, 10. 20)

Since (H)(S) = 6 H represents one of the individual numbers. And the factors of 6 are (1, 2, 3, 6)

The only number that is the same in each group of factors is 2

So H = 2. Now we can replace H with the number 2

(H)(N)=20 is (2)(N) = 20; Then you divide both sides by 2 and you get

(2)(N)/2 = 20/2 ; the 2 on the left side cancel each other and 20/2 = 10

N =10

You do the same process for (H)(S) = 6

(2)(S) = 6

(2)(S)/2 = 6/2

S = 3

(N)(S) = ?

(10)(3) = 30 cm

so 30 cm is the answer

User Gabriel Llamas
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