Question

Please help im stuck on these two… worth 20 points!

Answer 1

1. It's given that vz is angle bisector of angle WVU. That's means,

`\sf\angle \: wvz = \angle \: zvu`

It is also provided that angle zvu = 60°

Therefore, angle wvz = 60°

We can see that angle WVU is constituted of angle wvz and angle zvu.

Therefore, angle wvu = 60° + 60° = 120°

2. Given,

• angle TUJ = 95°
• angle TUV = 175°
• angle VUJ = x

Therefore,

We know that,

sum of all angles = 360°

Therefore,

angle TUJ + angle TUV + angle VUJ = 360°

Putting the values we have,

95° + 175° + x = 360°

x = 360° - 270°

x = 90°

Now,angle VUJ = 90°

and JUT = angle TUJ. = 95°

Therefore, angle JUT is greater than angle VUJ.

Hope it helps you mate :)