Question

13. Find the equation of the line through the points (3, -1) and (6, 7).

Answer 1

Ans:8x-3y=27

Explanation:

let,A,B be the line which have points (3,-1),(6,7)

here,

(3,-1)=(x1,y1)

(6,7)=(x2,y2)

then,

slope of line AB =(y2-y1/x2-x1)

=(7+1/6-3)

=8/3

Now,

equation of the line AB,

(y-y1)=m(x-x1)

(y+1)=8/3(x-3)

3y+3=8x-24

-8x+3y=-24-3

-8x+3y=-27

-(8x-3y=27)

8x-3y=27

Hence, the equation of the line through the points (3,-1) ,(6,7) is 8x-3y=27.