Question

What is the distance between (-8, 5) and (6, 5)?

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___ Units

Answer 1

We know that:

`\text{Distance }=\sqrt{(x_2-x_1)^(2) +(y_2-y_1)^(2)}`

Finding the coordinates

• (x₁,y₁) = (-8,5) = x₁ = -8; y₁ = 5
• (x₂,y₂) = (6,5) = x₂ = 6; y₂ = 5

Substitute the coordinates into the distance formula.

`\text{Distance }=\sqrt{(x_2-x_1)^(2) +(y_2-y_1)^(2)}`

`\rightarrow \text{Distance }=\sqrt{[(6- (-8)]^(2) +[5-5]^(2)}`


`\rightarrow \text{Distance }=\sqrt{[(6 + 8]^(2) +[0]^(2)}`


`\rightarrow \text{Distance }=\sqrt{[14]^(2)`


`\rightarrow \boxed{\text{Distance }=14 \ \text{units}}`

Answer 2

distance: 14

Step-by-step explanation:

`\sf √((y_2-y_1)^2+(x_2-x_1)^2)`

given:

• (-8, 5) and (6, 5)

solve:

`\sf \rightarrow √((5-5)^2+(6--8)^2)`

`\sf \rightarrow √((0)^2+(14)^2)`

`\sf \rightarrow √(14^2)`

`\sf \rightarrow 14`