Question

How many grams of NaOHare needed to prepare 30.0 ml of a solution with a molarity of 2.20 M?

Answer 1

2.64 grams

Step-by-step explanation:

Concentration = moles / volume of solution

So

moles = concentration (moles/liter) X volume of solution (liters)

30mL = 0.030 L

moles = 2.2 (moles/liter) X 0.030 (liter) notice the liters cancel out

moles = 0.066 moles

Mass of sodium hydroxide is 40 grams/mole

grams of NaOH = 0.066 moles x 40 grams/mole (the moles cancel out)

grams of NaOH = 2.64 grams