Answer:
1.50 Hours
Explanation:
Given:
- → The price of Stock A at 9 A.M. was $12.41.
- → Since then, the price has been increasing at the rate of $0.12 each hour.
- → At noon the price of Stock B was $13.16.
- → It begins to decrease at the rate of $0.14 each hour.
To Find:
If the two rates continue, in how many hours will the prices of the two stocks be the same?
Solve:
Price of stock A at 9 a.m.= $12.41
The price has been increasing at the rate of $0.12 each hour.
Increase in price after 3 hours = 0.12 × 3 = 0.36
Price of Stock A at noon= 12.41+0.36 =12.77
Let n be the no. of hours after which the prices of both the stocks will be same .
So, Increase in price after n hours = 0.12 n
Price of Stock A after n hours = 12.77+0.12 n
Price of stock B = 13.16
The price has been decreasing at the rate of $0.14 each hour.
Let n be the no. of hours
So, Increase in price after n hours = 0.14 n
Price of Stock B after n hours =13.16-0.14 n
ATQ
12.77 + 0.12n = 13.16 - 0.14n
-12.77 + 13.16 = 0.12n + 0.14n
0.39 = 0.26n
0.39/0.26 = n
n = 1.50
Hence the prices of the two stocks be the same after 1.50 hours after 12 pm .
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