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If the radius of a circle is decreased by 20%, find the percentage decrease in its area.​

1 Answer

6 votes

Answer:

36%

Explanation:

Area of circle is


\pi {r}^(2)

If the radius is decreased by 20%. Then the radius will be

80% of the original radius.

So our radius is 0.8.

So our area is


\pi(0.8r) {}^(2)


\pi(0.64 {r}^(2) )

Since pi is constant, the radius only really matters.

We went from


1 {r}^(2)

to


0.64 {r}^(2)

So our area will decrease by 36%

Proof: Let the radius be 10.

So the area of circle will be


\pi(10) {}^(2) = 100\pi

Let our other radius is 8 because 8 is a 20% decrease of the orginal radius


\pi(8) {}^(2) = 64\pi

Next, we subtract the area to find decrease in area


100\pi - 64\pi = 36\pi

Since pi is constant, we can ignore it so our decrease in area is 36%

User Bas Swinckels
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