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một lớp học có 25 học sinh giỏi toán, 23 học sinh giỏi lý, 14 học sinh giỏi cả 2 môn và 6 học sinh không giỏi môn nào. Hỏi lớp đó có bao nhiêu học sinh

User Benf
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2 Answers

5 votes

Answer:

I dont understand what you says

Explanation:

I only speak eng not other language

User Aro
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2 votes

The number of students in the class, given those good at math, physics, both and none, would be 40 students.

How to find the number of students ?

To determine the total number of students in the class, you can use the principle of the Inclusion-Exclusion Principle, which accounts for students who are good at math, physics, both subjects, and neither subject.

M = 25 (students good at math).

P = 23 (students good at physics).

B = 14 (students good at both subjects).

N = 6 (students good at neither subject).

Use the Inclusion-Exclusion Principle:

Total Students = M + P - B + N

Total Students = 25 + 23 - 14 + 6

Total Students = 40

In conclusion, there are 40 students in the class.

The full question is:

A class has 25 students good at math, 23 students good at physics, 14 students good at both subjects and 6 students good at neither subject. Ask how many students there are in that class

User Alexandrius
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