Please solve this...... \frac{ {c}^(2) + 2cd - {15d}^(2) }{ {4c}^(2) + 20cd }

asked Mar 22, 2022 195k views

2 votes

Please solve this......

$\frac{ {c}^(2) + 2cd - {15d}^(2) }{ {4c}^(2) + 20cd }$

3.5k points

Please log in or register to add a comment.

3 votes

Answer:

$\frac{ {c}^(2) + 2cd - 15 {d}^(2) }{4 {c}^(2) + 20cd} = ((c - 3d)(c + 5d))/(4c(c + 5d) ) \\ \\ \\ = (c - 3d)/(4c)$

I hope I helped you^_^

I Bajwa PHD answered Mar 27, 2022

3.8k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.6m questions

4.7m answers