Question

Please solve this......


`\frac{ {c}^(2) + 2cd - {15d}^(2) }{ {4c}^(2) + 20cd }`
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Answer 1

`\frac{ {c}^(2) + 2cd - 15 {d}^(2) }{4 {c}^(2) + 20cd} = ((c - 3d)(c + 5d))/(4c(c + 5d) ) \\ \\ \\ = (c - 3d)/(4c)`

I hope I helped you^_^