16x^0 + 2x^2 • y ^–1

asked Feb 18, 2022 186k views

2 votes

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6 votes

Answer:

16+2x^2/y

Explanation:

Vojko answered Feb 18, 2022

by Vojko

3.7k points

4 votes

Answer:

$16 {x}^(0) + 2 {x}^(2) {y}^( - 1) \\ = 16 + 2\frac{ {x}^(2) }{y} (anyting \: power \: 0 = 1 ) \\ thank \: you$

Dizzle answered Feb 23, 2022

4.2k points

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