188k views
0 votes
How much of an alloy that is 30% copper should be mixed with 600 ounces of an alloy that is 60% copper in order to get an alloy fratis

40 copper?
ounces

User Madarch
by
8.5k points

1 Answer

4 votes

9514 1404 393

Answer:

1200 ounces

Explanation:

Let x represent the weight of 30% copper that needs to be added to the mix. Then the total weight will be (600+x) ounces, and the amount of copper in the mix is ...

0.30x +0.60(600) = 0.40(600 +x)

0.3x +360 = 240 +0.4x . . . . . simplify

120 = 0.1x . . . . . . . . . . . . . subtract 0.3x+240

1200 = x . . . . . . . . . . multiply by 10

1200 ounces of 30% copper should be added to the mix.

User Joel Falcou
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories