Answer:
Solution
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f(x)=∣x−2∣+∣x−3∣
x<2 f(x)=2−x+3−x
=5−2x
2≤x<3 f(x)=x−2+3−x
=1
x≥3 f(x)=x−2+x−3
=2x−5
f(x)=
⎩
⎪
⎨
⎧
5−2x
1
2x−5
x<2
2≤x<3
x≥3
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