Question

Find the equation of a line that passes through the point (3,4) and has a gradient of 13. Leave your answer in the form y=mx+c​

Answer 1

`y=13x-35`

Explanation:

`m=13`

`(x_(1),y_(1))=(3,4)`

`y-y1=m(x-x1)`

`y-4=13(x-3)`

`y-4=13x-39`

`y=13x-35`

Answer 2

`y=13x-35`

Explanation:

Use the point-gradient form of a linear equation:
`y-y_1=m(x-x_1)`

(where
`m` is the gradient and
`(x_1,y_1)` is a point on the line)

Given:

• 
  `m = 13`
• 
  `(x_1,y_1)=(3,4)`

`\implies y-y_1=m(x-x_1)`

`\implies y-4=13(x-3)`

`\implies y-4=13x-39`

`\implies y=13x-35`