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\frac15 (4 - 3x) =\frac15 (3x - 4)

User Zuriel
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\huge \boxed{\mathbb{QUESTION} \downarrow}


  • \large\sf\frac15 (4 - 3x) =\frac15 (3x - 4)


\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}


\frac15 (4 - 3x) =\frac15 (3x - 4) \\

Cancel out 1/5 on both the sides.


4-3x=3x-4

Subtract 3x from both sides.


4-3x-3x=-4

Combine -3x and -3x to get -6x.


4-6x=-4

Subtract 4 from both sides.


-6x=-4-4

Subtract 4 from -4 to get -8.


-6x=-8

Divide both sides by -6.


x=(-8)/(-6) \\

Reduce the fraction -8/-6 to its lowest terms by extracting and cancelling out -2.


\huge \boxed{ \boxed{\bf \: x=(4)/(3) \approx 1.33 }}

User SatelBill
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