Question

Pls help and no unnecessary typin* I will report

Answer 1

`\large\bf{\underline{Given :}}`

• An isosceles triangle ABC
• AD is a bisector of ∠‎A

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`\large\bf{\underline{To \:prove :}}`

• BD = DC

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`\large\bf{\underline{In \: triangle \: ABD\:and\: triangle\:ADC}}`

`{⟹AD = AD\:\:\:\:\:\:\:\:\:\:\:\:\:\:( common)}`

`{⟹∠BAD = ∠CAD\:\:\:\:\:\:\:\:\:( given : AD \:is \:bisector \:of \:∠A )}`

`{⟹∠ABD = ∠ACD\:\:\:\:\:\:\:\:\:( given : angles\: in \:isosceles\: trianlge )}`

`\large\bf{\underline{Hence}}`

• By ASA criteria ∆ABD congurant to ∆ADC

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`\large\bf{\underline{So}}`

• By CPCT ( corresponding parts of congurant triangle )

`\large\bf{BD = DC}`

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`\large\bf{\underline{Note :}}`Slide to view full answer.