Question

5. Write an equation that passes through
(-2,-2), perpendicular to -2y - 10x = -9

Answer 1

y =
`(1)/(5)`x -
`(8)/(5)`

(hopefully this is correct! have a nice day :DD )

Explanation:

First we need to get the equation into y=mx+b form

(given) -2y - 10x = -9

(add 9 & 2y to both sides) 9 - 10x = 2y

(flipping it) 2y = -10x + 9

(dividing both sides by 2) y = -5x + 4.5 (or 4 1/2)

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Perpendicular lines have opposite sign reciprocal slopes, so the equation so far is:

y =
`(1)/(5)`x + b

To find our b (y-axis intercept) we will plug in the points given

(equation) y =
`(1)/(5)`x + b

(plug-in) -2 =
`(1)/(5)`(-2) + b

(multiply) -2 = -
`(2)/(5)` + b

(add 2/5 to both sides) -
`(8)/(5)` = b

(answer) b = -
`(8)/(5)`

(plug-in b) y =
`(1)/(5)`x -
`(8)/(5)`