Question

What is the answer????

Answer 1

S O L U T I O N:

Let's assume that the given rectangle be ABCD and in that let ∆ABC be the right angled triangle formed from it.

Now we've been asked to find out the breadth. By applying Pythagoras theorem here in our rectangle ABCD we have,

• length (l) = 30cm

• diagonal (d) = 34cm

• breadth (b) = ?

`:\implies\tt{ {b}^(2) = {d}^(2) - {l}^(2) }`

`:\implies\tt{ {b}^(2) = {34}^(2) - {30}^(2) }`

`:\implies\tt{ {b}^(2) = 1156 - 900}`

`:\implies\tt{ {b}^(2) = 256}`

`:\implies\tt{b = √(256) }`

`:\implies\tt{b = 16}`

For the formula of area (a) = ? it is given by,

`:\implies\tt{a = l * b}`

`:\implies\tt{a = 30 * 16}`

`:\implies\tt{a = 480 {cm}^(2) }`

For the formula of perimeter (p) = ? is given by,

`:\implies\tt{p = 2 * (l + b)}`

`:\implies\tt{p = 2 * (30 + 16)}`

`:\implies\tt{p = 2 * 46}`

`:\implies\tt{p = 92cm}`

• The breadth, area and perimeter of rectangle is 16, 480cm² and 92cm.

Answer 2

Explanation:

To find the breadth use Pythagorean theorem

Breadth² = diagonal² - length²

= 34² - 30²

= 1156 - 900

= 256

Breadth = √256 = 16 cm

Breadth = 16 cm

Perimeter = 2*(length + breadth) = 2*(30 + 16) = 2*46 = 92 cm

Area = length * breadth = 30 *16 = 480 cm²