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What is the answer????

What is the answer????-example-1
User PaPu
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S O L U T I O N:

Let's assume that the given rectangle be ABCD and in that let ∆ABC be the right angled triangle formed from it.

Now we've been asked to find out the breadth. By applying Pythagoras theorem here in our rectangle ABCD we have,

  • length (l) = 30cm

  • diagonal (d) = 34cm

  • breadth (b) = ?


:\implies\tt{ {b}^(2) = {d}^(2) - {l}^(2) }


:\implies\tt{ {b}^(2) = {34}^(2) - {30}^(2) }


:\implies\tt{ {b}^(2) = 1156 - 900}


:\implies\tt{ {b}^(2) = 256}


:\implies\tt{b = √(256) }


:\implies\tt{b = 16}

For the formula of area (a) = ? it is given by,


:\implies\tt{a = l * b}


:\implies\tt{a = 30 * 16}


:\implies\tt{a = 480 {cm}^(2) }

For the formula of perimeter (p) = ? is given by,


:\implies\tt{p = 2 * (l + b)}


:\implies\tt{p = 2 * (30 + 16)}


:\implies\tt{p = 2 * 46}


:\implies\tt{p = 92cm}

  • The breadth, area and perimeter of rectangle is 16, 480cm² and 92cm.
User ABHISHEK THEPRA
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4 votes

Answer:

Explanation:

To find the breadth use Pythagorean theorem

Breadth² = diagonal² - length²

= 34² - 30²

= 1156 - 900

= 256

Breadth = √256 = 16 cm

Breadth = 16 cm

Perimeter = 2*(length + breadth) = 2*(30 + 16) = 2*46 = 92 cm

Area = length * breadth = 30 *16 = 480 cm²

User Mylescc
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