117k views
2 votes

\lim _(n\to \infty \:)\left(\sqrt[n]{(n^2+1)/(n+1)}\right)

Please show your work!
Thank you! :)

1 Answer

0 votes

Answer:


\displaystyle \lim _(n\to \infty )\sqrt[n]{(n^2+1)/(n+1)} = \boxed1

Explanation:

we want to compute the following limit:


\displaystyle \lim _(n\to \infty )\sqrt[n]{(n^2+1)/(n+1)}

well, remember that, for limits to infinity, terms less than the highest degree of the numerator or denominator can be disregarded, hence we can drop 1 which yields:


\displaystyle \lim _(n\to \infty )\sqrt[n]{(n^2)/(n)}

reduce fraction:


\displaystyle \lim _(n\to \infty )\sqrt[n]{n}

by using limit formula, we acquire:


\displaystyle \lim _(n\to \infty )\sqrt[n]{n} = \boxed1

and we're done!

User Mateu
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories