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\lim _(n\to \infty \:)\left(\sqrt[n]{(n^2+1)/(n+1)}\right)

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Answer:


\displaystyle \lim _(n\to \infty )\sqrt[n]{(n^2+1)/(n+1)} = \boxed1

Explanation:

we want to compute the following limit:


\displaystyle \lim _(n\to \infty )\sqrt[n]{(n^2+1)/(n+1)}

well, remember that, for limits to infinity, terms less than the highest degree of the numerator or denominator can be disregarded, hence we can drop 1 which yields:


\displaystyle \lim _(n\to \infty )\sqrt[n]{(n^2)/(n)}

reduce fraction:


\displaystyle \lim _(n\to \infty )\sqrt[n]{n}

by using limit formula, we acquire:


\displaystyle \lim _(n\to \infty )\sqrt[n]{n} = \boxed1

and we're done!

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