Final answer:
To find the time it takes for the volleyball to hit the ground, we can use the equation y = y0 + v0y * t + (1/2) * a * t^2 for vertical motion. The time is approximately 0.91 seconds. The velocity of the ball at impact is approximately -5.26 m/s in the downward direction.
Step-by-step explanation:
To solve this problem, we can break down the motion of the volleyball into horizontal and vertical components. The velocity in the horizontal direction remains constant at 15 m/s, while the velocity in the vertical direction changes due to the acceleration due to gravity (-9.8 m/s²).
Using the equation y = y0 + v0y * t + (1/2) * a * t^2 for vertical motion, we can find the time it takes for the volleyball to hit the ground. In this case, the initial vertical position (y0) is 2.2 m, the initial vertical velocity (v0y) is 15 * sin(55°), and the acceleration (a) is -9.8 m/s². Solving for t, we find that it takes the ball approximately 0.91 seconds to hit the ground.
To find the velocity of the ball at the instant it strikes the ground, we can use the equation v = v0 + a * t for vertical motion. The initial vertical velocity (v0) is 15 * sin(55°), the acceleration (a) is -9.8 m/s², and the time (t) is 0.91 seconds. Plugging in these values, we find that the velocity of the ball at impact is approximately 15 - 9.8 * 0.91 = -5.26 m/s, where the negative sign denotes the fact that the ball is moving in the downward direction.