Answer:
(x+y+z)
2
=x
+y
+z
+2xy+2yz+2zx [Identity]
Here,
x=2a
y=3b
z=4c
Putting Values in Identity, We get :
⇒ (2a+3b+4c)
=(2a)
+(3b)
+(4c)
+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)
=4a
+9b
+16c
+12ab+24bc+16ca
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